Question

when 25 mg of k2so4 dissolved in 1 liter of water at 25°c then calculate osmotic pressure of solution​

Answer 1

Answer:

iridium copper do day to day day day day day

Answer 2

Given:

The mass of K2SO4, w = 25 mg = 0.025 gm

The volume of water, V = 1 litre

Temperature, T = 25°C = 25+273 = 298 K

To Find:

The osmotic pressure of the given K2SO4 solution​.

Calculation:

- The molar mass of K2SO4 = 174 gm/mol

- The molarity of K2SO4 solution:

M = (w × 1000)/(M.wt × V)

M = (0.025 × 1000)/(174 × 1000)

M = 0.025/174

- Osmotic pressure = CRT

⇒ Π = (0.025/174) × 0.082 × 298

⇒ Π = 0.003511 atm

⇒ Π = 3.511 × 10⁻³ atm

- So, the osmotic pressure of the given K2SO4 solution​ is 3.511 × 10⁻³ atm.