When 250.0 mL each of H 2 gas and O 2 gas at STP were mixed and ignited with an electric spark, only 125.0 mL of O 2 gas were left unused, and the rest changed into water. Given that weight of 22400 mL of H 2 at STP 2 g and O 2 =32 g
show that the data is following the law of definite proportion
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Explanation:
Let the formula of the ammonia be NH
3
.
The reaction for the decomposition of ammonia is 2NH
3
→N
2
+3H
2
.
Thus 2 moles of ammonia will give 4 moles of products.
Hence, 10 ml of ammonia will give 20 ml of products.
This is actually obtained during sparking.
15 ml of this is hydrogen gas which will use 7.5 ml of oxygen added, to form 15 ml of liquid water. Hence, 22.5 ml of oxygen and 5 ml of nitrogen will be left, which is equal to a total volume of 27.5 ml, as we got in the question.
Hence, the formula of ammonia is correct as NH
3
.
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