Question

When 2g of benzene are burnt in a bomb calorimeter, the heat produced is 83.6 kJ at 298 K. Calculate the enthalpy of combustion of benzene.

Answer 1

Answer:

hope it may help u.........

Answer 2

The enthalpy of combustion of benzene is -3215.4 kJ/mol

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of benzene = 2 g

Molar mass of benzene = 78.11 g/mol

Putting values in above equation, we get:

$\text{Moles of benzene}=\frac{2g}{78.11g/mol}=0.026mol$

To calculate the enthalpy change of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

$q$ = amount of heat released = -83.6 kJ

n = number of moles = 0.026 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction

Putting values in above equation, we get:

$\Delta H_{rxn}=\frac{-83.6kJ}{0.026mol}=-3215.4kJ/mol$

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