Question

when 2g. of H2 reacts with 10g. of oxygen then who is the limiting reagent and how much water is produced​

Answer 1

Explanation:

2H2+O2 =>2H2O.

2 moles of Hydrogen(H2) reacts with one mole of Oxygen(O2) to produce 2 moles of Water. Hence no. of moles of H2 weighing

2 grams =>2/2=>1 mole. No. of moles of O2 weighing 10 grams =>10/32 =>5/16. Hence the limiting reagent is Oxygen(O2). Hence 5/16 moles of O2 reacts with 5/8 moles of H2 to produce 5/8 moles of Water. 5/8 moles of Water weighs 5/8(18) =>11.25 grams. Water produced is 11.25 grams. Hope it helps you.