when 2kg of water is heated by providing 8kJ of heat,the change in temperature is?
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The formula that will be used is
Q = msΔθ
Q= 8 KJ
m= 2 Kg
The specific heat of water is 4200 J/Kg °C.
Putting the values in the formula,
8 KJ= 2 × 4200 × ΔΘ
8000 = 2 × 4200 × ΔΘ
ΔΘ= 80/84
= 0.95
The change in temperature will be 0.95
Answered by
1
Given:
When 2kg of water is heated by providing 8kJ of heat
Find:
The change in temperature is?
Solution:
We have the formula that will be used is
Q = msΔθ
Q= 8 KJ
m= 2 Kg
The specific heat of water is 4200 J/Kg °C.
Putting the values in the formula,
8 KJ= 2 × 4200 × ΔΘ
8000 = 2 × 4200 × ΔΘ
ΔΘ= 80/84
= 0.95
Hence, The change in temperature will be 0.95.
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