Math, asked by ddr1cuber, 8 months ago

When 2x³+5x²-2x+8 is devided by (x-a) the remainder is 2a³+5a² find the value of a

Answers

Answered by studyking7
4

= ( 2x³ + 5x² - 2x + 7 ) + ( x³ + 4x² - x + 6)

= 2x³ + 5x² - 2x + 7 + x³ + 4x² - x + 6

= 2x³ + x³ + 5x² + 4x² - 2x - x + 7 + 6

= 3x³ + 9x² - 3x + 13

Answered by Anonymous
3

Step-by-step explanation:

3xcibe +9xsq -3x +13 is your answer .......

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