Question

When 3.0g of corban is bunt in 8.00 g oxygen, 11..004 of carbon dioxide is produced. What mass of carbon dioxide will be formed when 3.00 g of carbon is burnt in 50.00g of oxygen ? Which law of chemical combination will govern your answer ?


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Answer 1

Answer:

$\huge\star\blue{QUESTION: }$

➡When 3.0g of corban is bunt in 8.00 g oxygen, 11..004 of carbon dioxide is produced. What mass of carbon dioxide will be formed when 3.00 g of carbon is burnt in 50.00g of oxygen ? Which law of chemical combination will govern your answer ?

$\huge\star\red{ANSWER:-}$

➡C+O ²➡CO²

•3g •8g •11g

=Total mass of reactants = mass of carbon + mass of oxygen =3+8=11g

=Total mass of reactants = Total mass of products

•Hence, the law of conservation of mass is proved.

=Further, it also shows carbon dioxide contains carbon and oxygen in a fixed ratio by mass, which is 3:8.

=Thus it also proves the law of constant proportions. 3 g of carbon must also combine with 8 g of oxygen only.

This means that (50−8)=42g of oxygen will remain unreacted

$\boxed{HOPE \: \: IT \: \: HELPS}$