Question

When 3^102 +3 is divided by 103 then the remainder Find out​

Answer 1

Answer: Fermat theorem says

3^102/103

= 1 remainder

So ,

(9 * 3^100)/103 = 1

(9 * X )/103 = 1

So it can written like this

x = (103k+1)/9

k is any value which is divisible by this equation

x = (103* 2 +1)/9

x =23 __remainder

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