Question

When 3,3-dimethyl-2 butanol is treated with HBr carbons

Q. 11 the number of present in the major product formed is:​

Answer 1

When 3,3-dimethyl-2 butanol is treated with HBr the number of tertiary carbons present in the major product formed in the reaction is 2.

Explanation:

• A tertiary carbon is a carbon that is bonded to three more carbon atoms.

$\mathrm{CH}_{3} \mathrm{C}\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_{3}+\mathrm{HBr} \rightarrow \mathrm{CH}_{3} \mathrm{C}\left(\mathrm{CH}_{3}\right) \mathrm{CH}(\mathrm{Br})\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{3}$

• The major product formed is 2,3-dimethyl-2-bromobutane, in which the second and third carbon atoms are tertiary in nature.
• Therefore, there are 2 tertiary carbons are in the product.