When 3.6 gram of non-volatile solute ‘X” is dissolved in 90 g of water at 293 K, its vapour pressure is lowered by 0.4%.Relative lowering in vapour pressure is (Vapour pressure of water at 293 K 17.5mm Hg)
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the solut X dissolved is water in it
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Given: Mass of solute X dissolved in water = 3.6 g
Mass of water = 90 g
Lowering of Vapour Pressure = 0.4%
To Find : Relative lowering of pressure
Solution:
- The formula for relative lowering of Vapour Pressure (RLVP) is ;
RLVP = (1)
Where P = vapour pressure of solvent
= vapour pressure of solution
- P = 17.5 mm Hg (given)
- is 0.4% less than P
⇒ = P - P
⇒ =
Substituting these values in (1)
⇒ RLVP =
⇒ RLVP = =
Therefore Relative Lowering is 0.004.
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