Question

when 3 coins are tossed simultaneously write the probabilities of all the events​

Answer 1

When three coins are tossed the total number of possible combinations are

2³ = 8.

These combinations are HHH, HHT, HTH, THH, TTH, THT, HTT, TTT.

Answer 2

Answer:

Possibilities of all events = 8/1 or 8.

Step-by-step explanation:

Solution :

In tossing three coins, the sample space is given by

{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}

(a) Then all possible outcomes are =8

(b) Then number of possible outcomes=8

(c)Then the probability of getting at least one head=

numberoftotalpossibleoutcomes/

numberofpossibleoutcomesofoneheads = 8/3

(d)Then the probability of getting at least two heads=

numberoftotalpossibleoutcomes/

numberofpossibleoutcomesoftwoheads = 8/3

(e)Then the probability of getting no tail=

numberoftotalpossibleoutcomes/

numberofpossibleoutcomesofnotail = 8\1