When 3 consecutive natural numbers are added, the sum= 66. Find the numbers.
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Answer:
first consecutive no. be x .
second consecutive no. be x+1 .
third consecutive no. be x+2 .
A/Q -
x+x+1+x+2=66
3x+3=66
3x=66-3
3x=62
x=63/3
x=21
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