when 3 gram of mg reacts with excess Hcl the weight of hydrogen liberated is (at- wt of mg =24
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here the rxn will be Mg + 2HCl = MgCl2 + H2. given mass of mg = 3g M.M of mg = 24g so acc to question. no of moles = 3/24 = 1/8 1/8 = x/2 where x is the considerable wt. of H2 so x = 0.25g
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