Question

when 3 mole of a and 1 mole of B are mixed in a 1 litre vessel the following reaction takes place a + b is equals to 2 C the equilibrium mixture contains 0.25 mole of see what is the value of equilibrium constant for the reaction​

Answer 1

Answer:

Which five qualities you need if you were studying in inclusive school

Explanation:

Answer 2

Answer:

$K_{c} =0.0208$

Explanation:

Since the given equation is

$a+b \rightarrow 2c$

Number of moles are given for a,b and c which are 3 ,1 and 0.25 moles respectively.

Given Volume of solution is 1 litre.

$concentration\ of\ a = \dfrac{No.\ of\ moles}{Volume\ of\ solution} = \dfrac{3}{1}=3mol/l$

$concentration\ of\ b = \dfrac{No.\ of\ moles}{Volume\ of\ solution} = \dfrac{1}{1}=1mol/l$

$concentration\ of\ c = \dfrac{No.\ of\ moles}{Volume\ of\ solution} = \dfrac{0.25}{1}=0.25 mol/l$

$So,Equilibrium\ constant(K_{c}) = \dfrac{c^{2} }{ab} = \dfrac{0.25^{2} }{3\times 1} =0.0208$