when 30.0g of a non-volatile solute having the
empirical formula CH20 empirical formula CH2O are dissolved in 800 g of
water, the solution freezes at - 1.16°c , what is the
molecular formula of the solute (kf for water=
1.86 km-1)
Answers
Answer:
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Explanation:
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Answer:
Explanation:
ANSWER
we have
ΔT
f
=K
f
∗m
0.93 = 1.86 * m
molality =
molarmassofsolute∗massofsolvent
massofsolute
=
x∗1.2
36
we get,
0.93 = 1.86 *
x∗1.2
36
we get,
molecular weight = 60
we have empirical formula = CH
2
O$
and empirical formula mass = 30
therefore n=
30
60
= 2
so, molecular formula becomes = C
2
H
4
O
2