Question

when 32gms of CH4 is burned with excess oxygen ,how many g of CO2 are produced ​

Answer 1

Answer:

Explanation:

1 gram mole of CH4 = 1 gm mole of CO2. 7. How many grams of C2H6 are required to produce 88 grams of CO2 when it is burned in the excess of oxygen

Answer 2

Given:

32gms of CH4 is burned with excess oxygen.

To find:

Amount of CO2 produced.

Calculation:

First let's look at the equation:

$\boxed{\sf{CH_{4}+2O_{2}\rightarrow CO_{2}+2H_{2}O}}$

As per the balanced Equation:

1 mole of CH4 gives 1 mole of CO2

=> 16 gm of CH4 gives 44 gm of CO2

=> 32 gm of CH4 gives $\dfrac{44}{16}\times32$ gm CO2

So, amount of CO2 produced:

$\boxed{amount = \dfrac{44}{16} \times 32 = 88 \: gm}$

So, final answer is:

$\boxed{ \bf{weight \: of \: CO_{2} \: produced= 88 \: gm}}$