Question

When 35 gm of NH,OH is dissolved in 10 lit. of water,
then its degree of dissociation will be (K = 1.8 * 10-
(A) 1.34 x 10-3
(B) 1.34 x 10-2
(C) 4.24 x 10-2
(D) 4.24 x 10-3​

Answer 1

K= 1.8 × 10^(-5)

From the given information, the conc. Of NH4OH is 0.1 M.

So by putting the values in equation of K, we get,

K= x^2/0.1-x

=> 1.8 × 10^(-5) = x^2/0.1-x

=> x= 1.34 × 10^(-3)

So, degree of dissociation= x/C

= 1.34×10^(-3)/0.1

= 1.34×10^(-2)