Question

When 36 g of solute having empirical formula of ch2o is dissolved in 1.20kg of water?

Answer 1

Answer:when 36.0 g of a solute having an empirical formula CH2O is dissolved in 1.20 kg of water, the ... if the molecule does not dissociate in water i = 1 ... we have 36 g dissolved in 1.2 kg of solvent or 36 x 1/ 1.2 g / kg = 30 g / kg of solvent ... empirical mass = 12 +2 + 16 = 30 so there are 2 empirical units/ mole

Explanation:

Answer 2

−ΔTf=Kfm

⇒0.93K=(1.86KKgmol−1)(36g/M1.20kg)

This gives M=1.86×360.93×1.20gmol−1

n=Molar massEmpirical molar mass

=60gmol−130gmol−1=2

Hence,molecular formula is C2H4O2