When 3x^3-x^2-x-4 is divided by (x-1) what is the remainder
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Answered by
3
Heya user !!!
Here's the answer you are looking for
Let f(x) = 3x³ - x² - x - 4
f(x) is divided by (x - 1), so remainder is f(1)
f(1) = 3(1)³ - 1² - 1 - 4 = 3 - 1 - 1 - 4 = -3
Thus the remainder is -3.
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
Let f(x) = 3x³ - x² - x - 4
f(x) is divided by (x - 1), so remainder is f(1)
f(1) = 3(1)³ - 1² - 1 - 4 = 3 - 1 - 1 - 4 = -3
Thus the remainder is -3.
★★ HOPE THAT HELPS ☺️ ★★
Answered by
4
yes, I can help you !
3x² + 2x + 1
______________
x - 1 | 3x³ - x² - x - 4 |
| 3x³ - 3x² |
_______________
2x² - x - 4
2x² - 2x
_______________
x - 4
x - 1
_______________
- 3
we found
→ remainder = - 3
→ decider = x - 1
_______________________________
3x² + 2x + 1
______________
x - 1 | 3x³ - x² - x - 4 |
| 3x³ - 3x² |
_______________
2x² - x - 4
2x² - 2x
_______________
x - 4
x - 1
_______________
- 3
we found
→ remainder = - 3
→ decider = x - 1
_______________________________
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