When 3x³-8x² + 10x- k is divides by x-2, thr remainder is 18. What would be the value of k?
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Answers
Answer:
Here, The value of k is 12.
Step-by-step explanation:
Here, As per our given question,
=P(x)=3x^3-8x^2+10x-k=0
And it is divided by, g(x)=x-2
So,=x-2=0
=x=2
By putting the value of x in p(x), we get,
=3×(2)^3-8×(2)^2+10×(2)-k=0
=3×8-8×4+20-k=0
=24-32+20-k=0
=44-32-k=0
=12-k=0
=(-k)=(-12)
=k=12 (As both sides are equal and have same sign of -)
So, Here, The value of k=12.
Thank you.
Solution:-
:- Given Equation
=> 3x³ - 8x² + 10x - k is divided by x - 2
=> Remainder = 18
:- Now take
=> x - 2 = 0
=> x = 2
:- Put the value of x on equation and the equation is equal to 18
=> f(2) = 3x³ - 8x² + 10x - k = 18
=> 3 × (2)³ - 8 × (2)² + 10 × 2 - k = 18
=> 3 × 8 - 8 × 4 + 20 - k = 18
=> 24 - 32 + 20 - k = 18
=> 44 - 32 - k = 18
=> 12 - k = 18
=> - k = 18 - 12
=> - k = 6
=> k = -6
:- Value of k is - 6