Question

when 4.2 g Nahco3 reacts with 10 g acetic acid,C02 formed is 2.2 g and mass solution is 12g.Show that these data confirm law of conservation of mass.

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Answer 1

Answer:

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Explanation:

according to law of conservation of mass

NaHCO3 + CH3COOH = Co2 + residue

4.2g + 10.0g. = 2.2g + 12.0g

14.2g. = 14.2g

So the masses are same before and after the reaction therefore results agree with the law of conservation of masses

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Answer 2

The law of conservation of mass actually states that the total mass of the reacting substances also known as reactants are always equal to the total mass of the products formed after the reaction.

Here, we can prove this by our logical calculation.

NaHCO3 (Sodium hydroxide) and CH3COOH (Acetic acid) are the reacting substances or reactants here. Their total mass = (4.2+10) g = 14.2 g

Similarly, the total mass of the products which are formed after reaction = (2.2+12) g = 14.2 g

Thus, we are observing that the total mass of the reactants and products are remaining constant. Hence, the above given data strictly confirms the law of conservation of mass.