Question

When 4.5 g of sodium carbonate reacts with 5 g of acetic acid, the
products formed are 6.5 g of sodium acetate, 0.6 g of water, and 2.4 g of
carbon dioxide. Mention the law which this reaction abides and explain
how?

Answer 1

Given :-

When 4.5 g of Sodium Carbonate (NaCO3) reacts with 5g of acetic acid(CH₃COOH) gives 6.5 g of sodium acetate, 0.6 g of water, and 2.4 g of carbon dioxide.

Reaction :-

NaCO3 + CH₃COOH -------> C2H3NaO2 + H2O + CO2

4.5 g + 5 g -------> 6.5 g + 0.6 g + 2.4 g

9 g = 9g

Hence,

The mass of product is equal to the mass of reactant.

Therefore, it verifies the law of conservation of Mass.

As this law says, Mass can neither be created nor be destroyed in any reaction.