Question

when 4 moles of C react with 2 moles of oxygen to form carbon monoxide , what will be volume of the gas formed at 273 K and 1 atm ?

Answer 1

Answer :

4 moles of C reacts with 2 moles of oxygen to form carbon monoxide.

We have to find volume of carbon monoxide gas at STP$.$

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◈ Balanced chemical reaction :-

$\underline{\boxed{\bf{\orange{2C+O_2}\:\longrightarrow\:\purple{2CO}}}}$

It is clear from the reaction that,

2 moles of C reacts with 1 mole of O₂ to form 2 moles of CO.

2 moles of C gives 2 moles of CO

Hence, 4 moles of C gives 4 moles of CO.

◈ Volume of 4 moles of CO :

• Volume = Moles × 22.4
• Volume = 4 × 22.4
• Volume = 89.6L

Answer 2

Answer:

89.6 L

Explanation:

2 moles of Carbon + 1 mole oxygen = 2 moles of Carbon monoxide

We get 2 moles CO from 2 moles C

therefore, we can get 4 moles CO from 4 moles C

Now we know ,

Volume= Moles × 22.4 = 4 × 22.4 = 89.6 L