Question

When 4 ohm,6ohm and 8 ohm are connected in circuit find the minimum and maximum resistance possible.

Answer 1

For the given connection of resistors, The maximum possible resistance is when they are in series arrangement. The minimum possible resistance is when they are in parallel arrangement.

In series : The resistance offered by the combination is more than the individual resistance.

Let R be the equivalent resistance,

R is given by R = R₁ + R₂ + R₃

So, R = 4 + 6 + 8 = 18

In parallel, The resistance offered by the combination is less than the individual resistance.

Let R be the equivalent resistance,

R is given by 1/R = 1/ R₁ + 1/R₂ +1/ R₃

So, 1/R = 1/4 + 1/6 + 1/8

1/R = 6/24 + 4/24 +3/24

1/R = 13/24

R = 24/13 Ohms.

Therefore, The minimum and maximum resistance offered by 4,6,8 ohm resistors is 24/13 , 18 Ohms respectively

Answer 2

Answer:

Explanation:

Max.resistance (when connected in series)=4+6+8=18 ohm

Min.resistance (when connected in parallel)=1÷R=1÷4+1÷6+1÷8=1.8 ohm