Question

when 40 CC of slightly moist HCL gas is mixed with 20 CC of ammonia gas the final volume of gas left at the same temperature and pressure will be
A-20cc
B-50cc
C-60cc
D-100cc....reply wid hint

Answer 1

Volume will be same as 20 cc as NH3 is limiting ....HCl + NH3 = NH4Cl Which is totally balanced So HCl should also be 20cc ...HCl unreacted = 40-20 = 20 cc U can solve this by calculating moles also but this would only lead to complicated calculation

Answer 2

Answer: The correct answer is Option C.

Explanation:

The chemical equation for the reaction of hydrochloric acid and ammonia follows:

$HCl+NH_3\rightarrow NH_4Cl$

We are given:

Volume of HCl = 40 cc

Volume of ammonia = 20 cc

To calculate the total volume, we use Avogadro's law. This law relates the number of moles and volume at constant pressure and temperature.

$V\propto n$   (at constant pressure and temperature)

Total number of moles = Moles of hydrochloric acid + Moles of ammonia

Total number of volume = Volume of hydrochloric acid + Volume of ammonia = 40 cc + 20 cc = 60 cc

Hence, the correct answer is Option C.