Chemistry, asked by yashormasandal6263, 11 months ago

When 400 gram KCLO3 is heated,10 litre of O2 at 1 ATM and at 327 degree celsius is obtained what percentage of KCL O3 is decomposed?

Answers

Answered by kobenhavn
8

Answer: 4.08%

Explanation:

According to the ideal gas equation:'

PV=nRT

Pressure of the gas = 1 atm

Volume of the gas = 10 L

Temperature of the gas = 327°C = (327+273)K = 600K  (0°C = 273 K)

Value of gas constant in in kilopascals = 0.0821 Latm/K mol

n=\frac{PV}{RT}=\frac{1atm\times 10L}{0.0821\times 600}=0.20mol

2KClO_3(s)\rightarrow 2KCl(s)+3O_2(g)

3 moles of O_2  is produced from 2 moles of KClO_3

Thus 0.20 moles of O_2 is produced from =\frac{2}{3}\times 0.20=0.13moles of KClO_3

Mass of KClO_3=moles\times {\text {molar mass}}=0.13\times 122.5=16.3g

Thus percent of KClO_3 decomposed is =\frac{16.3}{400}\times 100=4.08%

4.08 % of  KClO_3 decomposed.

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