Question

When 400 Joule of heat is given to 50 g sample of a metal, its temperature increased by 20°C. If specific heat of metal is n × 50 J kg1°C1 then find the value of n ?​

Answer 1

Answer:

N×50=400*100/20*10

N=200/50

N=4

hope it helps you (•‿•)

Answer 2

Question:

When 400 Joule of heat is given to 50 g sample of a metal, its temperature increased by 20°C. If specific heat of metal is n × 50 J kg1°C1 then find the value of n ?

Answer:

N = 4

Explanation:

N × 50 = 400 × 100 ÷ 20 × 10

N × 50 = 40,000 ÷ 200

N = 200 ÷ 50

N = 4