Chemistry, asked by danizav470, 10 months ago

When 45 g of an alloy, at 25mc008-1.jpgC, are dropped into 100.0 g of water, the alloy absorbs 956 J of heat. If the final temperature of the alloy is 37mc008-2.jpgC, what is its specific heat?

Answers

Answered by Alongjr
0

Answer:

the special heat will be 1000.celcius

Answered by hananb
0

Answer:

Q = ms◇t

956 = 45.s. (37-25) = 540.s

So s = 956/540 = 1.77 J/g/°c

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