Question

When 45 is divided by x, the remainder is x-5. If x be a natural number, what are all the possible values of x?​

Answer 1

Answer:Let’s rewrite, and call x = 5y +3

I take it x^ means x square, i.e. x^2.

If so, we have: What is the remainder if we devide x^2 -5x + 2?

Now 5x is divided on 5, so it doesn’t contribute anything to the solution, so let’s leave it out. We are then left with

x^2 + 2 = (5y + 3)(5y + 3) + 2 = 25y^2 +30 y + 9 + 2

Again 25y^2 and 30y are divisible on 5, which leaves us

9 + 2 = 11. 11 divided on 5 gives a remainder of 1

The remainder when dividing x^2-5x+2 with 5, then is 1.

Step-by-step explanation:

Answer 2

Answer:

I think that it's the only answer to solve this