When 489 and 604 are divided by n remainders are 9 & 4 respectively then find maximum value of n?
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Answer:
⇒ Let the two numbers be a and b and the divisor be d.
⇒
d
a
=35(Remainder) ---- ( 1 )
⇒
d
b
=30(Remainder) ----- ( 2 )
⇒
d
a+b
=20(Remainder) ----- ( 3 )
∴ d=(
d
a
+
d
b
)−
d
a+b
[ According to the set theory ]
∴ d=(35+30)−20 [ From ( 1 ), ( 2 ) and ( 3 ) ]
∴ d=45
∴ Required divisor is 45
Step-by-step explanation:
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