Question

when 4g of a mixture of NahCo3 and NaCl is heated strongly 0.06 Co2 gas is evolved. Determine the percent composition of the original mixture ​

Answer 1

Answer:

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Explanation:

ANSWER

2NaHCO

3

=Na

2

CO

3

+CO

2

+H

2

O

Molar mass of NaHCO

3

=23+1+12+16×3=84 g/mol

2 moles of NaHCO

3

=2×84=168g

Molar mass of CO

2

=12+16×2=44g/mol

44g of CO

2

is produced from 168g of NaHCO

3

0.66g of CO

2

will be produced from =(0.66×168)/44

=2.52g

Percentage of NaHCO

3

in the mixture =(2.52/4)×100=63%

Percentage of NaCl in the mixture =100–63=37%