Physics, asked by khannameera441, 8 months ago

when 4j work is done on a body,initially at rest,of mass 2kgthen velocity of a body will become

Answers

Answered by mukeshkumar34225

1

Answer:

w=f.d

so, as= w/m = 4/2 =2

we know v^2 - u^2 = 2as

v=√2as=√4 = 2m/s

Explanation:

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