Question

When 5.29 g of a non-volatile solute was dissolved in 400 g of water, its freezing point decreased by 1.79 K.

Calculate the molecular wt of solute if Kf

for water is 1.86 K kg mol-1​

Answer 1

Explanation:

Freezing point of the solution =271.94 K

Freezing point of the solution =271.94 K Freezing point of water =273.0 K

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06K

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that,

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m=

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w Given,

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w Given, K

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w Given, K f

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w Given, K f

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w Given, K f =1.86 Kkgmol

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w Given, K f =1.86 Kkgmol −1

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w Given, K f =1.86 Kkgmol −1 ,

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w Given, K f =1.86 Kkgmol −1 , w=1.25g,

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w Given, K f =1.86 Kkgmol −1 , w=1.25g,W=20g ,

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w Given, K f =1.86 Kkgmol −1 , w=1.25g,W=20g ,△T=1.06K

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w Given, K f =1.86 Kkgmol −1 , w=1.25g,W=20g ,△T=1.06KNow,

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w Given, K f =1.86 Kkgmol −1 , w=1.25g,W=20g ,△T=1.06KNow,M=

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w Given, K f =1.86 Kkgmol −1 , w=1.25g,W=20g ,△T=1.06KNow,M= 20×1.06

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w Given, K f =1.86 Kkgmol −1 , w=1.25g,W=20g ,△T=1.06KNow,M= 20×1.061000×1.86×1.25

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w Given, K f =1.86 Kkgmol −1 , w=1.25g,W=20g ,△T=1.06KNow,M= 20×1.061000×1.86×1.25

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w Given, K f =1.86 Kkgmol −1 , w=1.25g,W=20g ,△T=1.06KNow,M= 20×1.061000×1.86×1.25

Freezing point of the solution =271.94 K Freezing point of water =273.0 K △T=(273−271.94)=1.06KWe know that, m= W×△T1000K f ×w Given, K f =1.86 Kkgmol −1 , w=1.25g,W=20g ,△T=1.06KNow,M= 20×1.061000×1.86×1.25 M=109.67 g/mol