Chemistry, asked by sudhanshumodi36, 9 months ago

When 5 gram of calcium is burnt in 2 gram of oxygen 7 gram of calcium oxide is formed. how much calcium oxide is formed when 37.5 gram of calcium is burnt in 20 gram of oxygen. Which law of chemical combination will govern your answer ? State the law.

Answers

Answered by Anonymous
1

Answer:

This is your answer

Explanation:

The reaction between oxygen and calcium is as follows:

2Ca  +  O₂   ----------------->   2CaO

The mole ratio of the above equation is :

2 : 1 : 2  which means that every 2 moles of calcium requires 1 mole of oxygen to form 2 moles of calcium oxide.

 moles of oxygen :

moles = mass/molar mass     ----->     2/32 = 0.0625 moles

moles of calcium:

moles = mass/molar mass --------->  5/40 = 0.25 moles

When 20 grams of oxygen is used:

find moles of 20g of oxygen

moles = mass/molar mass -----------> 20/32   = 0.625 moles

Therefore calcium is the limiting reagent --we will use its actual moles(which is 0.25) to calculate the mass of CaO produced.

The mole ratio between Ca used and CaO produced from the equation above is: 2 : 2 which is 1 to 1. This means that 1 mole of Ca will give 1 mole of CaO. 

Since the mole of Ca is 0.125, then mole of CaO produced will also be 0.125.

Mass = moles × molar mass

molar mass of CaO is 56

Therefore mass produced = 0.125 × 56

                                            = 7g

a) The mass of calcium oxide produced will be 7g since all the calcium will be used up but the oxygen will remain in excess.

b)  Law of conservation of mass will govern your answer...

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