When 5 liter nitrogen pressure is double and temperature 300 to 600 kelvin what is the final volume
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P*V = n*R*T
n = ( P*V) ÷ ( R*T)
because number of moles of gas is constant
P1 * V1 ÷ T1 = P2 * V2 ÷ T2
V2 = (P1÷P2) × ( T2 ÷ T1 ) × V1
V2 = (1/2)×(600/300)×5 = 5litre
V2 = litre
n = ( P*V) ÷ ( R*T)
because number of moles of gas is constant
P1 * V1 ÷ T1 = P2 * V2 ÷ T2
V2 = (P1÷P2) × ( T2 ÷ T1 ) × V1
V2 = (1/2)×(600/300)×5 = 5litre
V2 = litre
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