When 50.0 g of MgCO3 react completely with H3PO4, as shown below,15.8 g of CO2
are produced. What is the percent yield for this reaction?
2 H3PO4 + 3 MgCO3 Mg3(PO4)2 + 3 CO2 + 3 H2O
Answers
Answered by
4
Answer:
Explanation:
Limiting ratio = 0.1984
Moles of co2 = 0.5952
Moles of co2 produced = 0.359
So yield = 60 percent
Answered by
1
Answer: 60.5%
Explanation:
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