When 50 cm3 of 0.2 N H So, is mixed with 50 cm3 of 1N KOH, the heat liberated is
(1) 11.46 kJ
(2) 57.3 kJ
(3) 0.563 kJ
(4) 0.573 kJ
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Answer:(4) 0.575kj
Explanation: [H+](aq) + [OH-](aq)=H2O(l)
0.2mol/L[H+]*0.050L*57.3Kj/mol
=0.573KJ
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