Question

when 50 g urea is dissolved in water it forms 1000 g solution, find its molality?​

Answer 1

Molality = moles of solute/weight of solvent in kg

Mole of urea = weight/molar mass of urea

Molar mass of urea (NH2CONH2) is 60 g

so moles = 5/6

Now, mass of urea = 50 g

mass of solution = 1000 g

→ mass of solvent (water) = 1000-50 = 950 g = 0.95 kg

so molality = 5/6 ÷ 0.95

= 0.878 m

Answer 2

Answer:

☆●Answered by Rohith kumar. R. maths dude: -

▪Molarity = moles of solute

weight of solvent in kg

▪We know that

●Molar mass of urea (NH2CONH2)=60g

▪Therefore moles = 5

6

▪Here given that mass of urea= 50g.

▪and mass of solution =1000g.

●Therefore

▪Now,

▪Mass of solution-mass of urea=mass of solvent

▪1000-50=950g.

If we convert it into kg 950= 0.95kg..

▪Therefore the molarity= 5 ÷ 0.95

6

☆●Molarity=0.878m.

☆Hope it helps u mate.

☆Thank you.