Question

When 50 ml of 2M solution of N2O5 was heated, 0.28 L of O, at NTP was formed after 30 minutes. Calculate the concentration of N2O5 at that time and also find the average rate of reaction.​

Answer 1

Answer: N  

2

​

O  

5

​

→N  

2

​

O  

4

​

+1/2O  

2

​

 

50m  

2

2Mm=  

v

n

​

⇒n=m×v

=2(  

1000

50

​

)=0.1

1 moles N  

2

​

O  

5

​

 reacts to give 1 mole O  

2

​

 

i.e : no  

2

​

=  

22.4

0.28

​

=0.0125moleO  

2

​

 

0.0125moleN  

2

​

O  

5

​

 use

Remaining = (0.1−0.0125) mol

=0.0875 mol

Explanation: