Question

When 50% of a solution of a weak acid HA(Ka=10^-5) is neutralized using NaOH solution, the pH of the resulting mixture will be​

Answer 1

Answer:

5

Explanation:

a = 50 /100 = .5, K = 10^-5

a^2=kc

c = .25 × 10^-5 = 4×10^-5

pH = - log(ac) = -log(.5× 4×10^-5) = 4.69 =5(approx)