Question

when 50% of reactants in a reversible reaction are converted into product then the value of equilibrium constant Kc is​

Answer 1

Answer:

Hope you like the answer.

Explanation:

let initial mole = 1

after 50% it will be = 0.5 ( products)

now,

let, reaction is

A -----------> B

( 1 mole ) (0.5 mole)

Kc= reactant mole / products mole

Kc = 0.5 mole / 1 mole

Kc= 0.5 Answer

Answer 2

Answer:

Answer is Kc = 1

Explanation:

The explanation is quite basic.

Suppose a reversible reaction

A 《=======》B

[A] [B]

Initially 1 mol 0 mol

At some time "t"

(1 - 0.5) mol 0.5 mol

so, Kc = [B] / [A]

= 0.5 / 0.5

= 1