Question

When 50N load is applied in a 20mm diameter rod , then what will be the stress developed in it ?​

Answer 1

Given:  

D=20mm,   L=200mm  δd=0.0035mm(Lateral),    δl=0.1mm(Linear)

To Find  

μ=E=?

Solution:(i)μ=?μ=Lateralstrain/Linearstrain

Lateralstrain =δdd=1.75×10−4

Linearstrain =δll=5×10−4

μ=1.75×10−45×10−4

μ=0.35

E=P×LA×δl=50×103×200π4×202×0.1

=31.83×104N/mm2