Chemistry, asked by ruthamedie4, 2 months ago

when 52.7g of octane(C8H18) burns in oxygen, the percentage yield of carbon dioxide is 82.5%. what is the actual yield in grams.​

Answers

Answered by Anonymous
24

When 52.7 g of octane (c8 h18) burns in oxygen, the percentage yield of carbon dioxide is 82.5%. what is the actual yield in grams? mols C8H18 = grams/molar mass = approx 0.5 but that's just an estimate as are all the numbers that follow. mols CO2 produced = approx 0.5 x 16/2 = approx 4.

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Answered by naolabay96
2

Answer:

7

Explanation:

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