Question

when 6x^(2)+ax+7 is divided by x-2,the remainder is 13 .find the value of a​

Answer 1

Answer:

Substitute x=2 in the polynomial and equate it to 13.

$6 {x}^{2} + ax + 7 = 13 = > 6 {(2)}^{2} + a(2)$

$+ 7 = 13 = > 24 + 2a + 7 = 13 = >$

$= > 2a = 13 - 31 = - 18 = > a =$

$\frac{ - 18}{2} = - 9$

Hope it helps you.