Question

When 6x^2 + ax + 7 is divided by (x - 2) the remainder is 13, then the value of a is

Answer 1

Step-by-step explanation:

6x²+ax+7-13=(6x²+ax-6) it is devisible by (x-2)

that means-

(6×2²)+(a×2)-6=0

or 24+2a-6=0

or 2a+18=0

or a=-9