Math, asked by madhushukla642, 10 months ago

When 6x^2 + ax + 7 is divided by (x - 2) the remainder is 13, then the value of a is
a) 11
b) 12
c) 13
d) 14

Answers

Answered by predators
11

Answer:

Step-by-step explanation:

put x=2 because x-2=0

so 6*2^2+a2+7=13

24+2a+7=13

2a=-22

a=-11

hope it helps please mark it as brainliest

suhasarava3: its incorrect
suhasarava3: 13-24-7=-18. not -22
predators: ek thapad dunga sab theek ho jayega
madhushukla642: @predators thanks but the answer you gave is in negative but it is not in options...and the options cannot be wrong as this paper came in my test...please tell
Answered by suhasarava3
27

answer is -9

Step-by-step explanation:

given it is divided by x-2. so substitute x=2 for getting the remainder. 6*4+2a+7=13

24+2a+7=13

2a+31=13

2a=13-31

2a = -18

a=-9

madhushukla642: the answer should not be in negative according to the options..
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