Question

when 6x^2+kx+7 is divided by x-2, it leaves remainder 13.Find the value of k. ​

Answer 1

Answer:

hi

Step-by-step explanation:

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Answer 2

Answer:

-9

Step-by-step explanation:

x-2 =0

x = 2

6x²+ kx + 7 = 13

6(2)²+k(2)+ 7 = 13

24+2k +7 = 13

2k + 31 = 13

2k = 13 - 31

2k = -18

k = -9