when ( 77^77 ) +77
![{77}^{77} + 77 {77}^{77} + 77](https://tex.z-dn.net/?f=+%7B77%7D%5E%7B77%7D+%2B+77)
is devided by 78 ,then what is the remainder ?
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Answers
Answered by
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Step-by-step explanation:
let 77 be x => 78=77+1=x+1
x^x +x / x+1
f(x)=x^x+x when divided by x+1 remainder is f(-1)=-1^-1 -1=-2
remainder =-2
as remainder is-ve, you have to add 78
= 78-2=76 is the remainder
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