When 7g nitrogen reacts with 3g hydrogen to form ammonia .Find out amount of Ammonia and volume at STP
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N2 + 3H2———→2NH3
So 28 gm of N2 will react with 6 gm of H2, to form (2 moles) 34 gm of Ammonia.
So 7gm of N2 will react with=6 x7/28=1.5 gm. So the amount of Ammonia gas forward will be =7+1.5=8.5 gm.
7 gm of Nitrogen will react with only 1.5 gm of Hydrogen and will give 8.5 gm (0.5 mole) Ammonia. The rest 1.5 gm Hydrogen will be left unreacted.
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