Question

When 8.4 g of nahco3 on reaction with 20 g of CH3 COOh liberates 4.4 g of CO2 gas in atmosphere. what is the mass of residue ​

Answer 1

Answer:

Step by step

Explanation:

The mass of residue, is CH3COONa solution, should be 24g of CH3COONa solution.

In this reaction, sodium bicarbonate reacts with acetic acid to produce sodium acetate, carbon dioxide and water

NaHCO3+CH3COOH⟶CH3COONa+CO2+H2O

According to law of conversation of masses,

total masses of reactants = total masses of products

reactants are 8.4g NaHCO3 and 20g CH3COOH.

total mass of reactants is =28.4g

mass of residue = (28.4g reactants mass) − (4.4g CO2)

                            = 24.0g residue (sodium acetate solution)

mass of residue is thus 24 grams